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#1 |
Moderator
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Интересная проблема. Никогда с этим не сталкивался. Что за задача? Можно увидеть сами запросы?
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#2 |
Участник
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Вот, пожалуйста!
SELECT TJ.new_spstage,InStepTable.New_stepnumber as StepNumber,COUNT(*) as InForThisStep,(SELECT COUNT(*) FROM (SELECT * FROM FilteredNew_TransactionJournal as CRMAF_FilteredNew_TransactionJournal) as TJOut
INNER JOIN FilteredNew_stepofvoronka as OutStepTable ON (OutStepTable.New_Name=TJOut.new_spstage)AND(OutStepTable.New_voronka_step=TJOut.new_crater_stage) WHERE (TJOut.new_action=1) AND (TJOut.new_crater_stagename=@vorname) AND (OutStepTable.New_stepnumber=InStepTable.New_stepnumber-1) )as OutFromBeforeStep FROM (SELECT * FROM FilteredNew_TransactionJournal as CRMAF_FilteredNew_TransactionJournal) as TJ INNER JOIN FilteredNew_stepofvoronka as InStepTable ON (InStepTable.New_Name=TJ.new_spstage)AND(InStepTable.New_voronka_step=TJ.new_crater_stage) WHERE (TJ.new_action=0) AND (TJ.new_crater_stagename=@vorname) AND (TJ.new_spstage!='Потенциальное предложение') AND (InStepTable.New_stepnumber!=1) Group by TJ.new_spstage,InStepTable.New_stepnumber ORDER BY InStepTable.New_stepnumber |
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#3 |
Участник
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Думаю эту ситуацию можно обойти, создав два под-отчёта (Sub-report) и вложив их в основной отчёт.
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#4 |
Участник
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Пробовал уже, тоже не работает!
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